/* Example on counting loop and for statement. file: 3ex2.cpp FALL 1998 ___________________________________ Jacob Y. Kazakia jyk0 September 16, 1998 ___________________________________ Purpose: This program determines the positions where a given number of wooden posts are to be placed. The location of the beginning point and the location of the end point are read through the keyboard. The beginning and end points are marked by concrete minitowers The number of the posts to be placed on a straight line in between these two points is also read through the keyboard. The posts are placed at equal intervals. The location of each post is calculated and outputted to the screen. Algorithm: The location of the beginning point and the end point are given using coordinates xstart and xend in reference to a line connecting the two points with origin at a fixed point on this line. In order to simplify things we will require that xend > xstart. All coordinates will be given in feet. The distance between the start and the end is distance = xend - xstart If the number of posts to be placed in between is postnumber then the distance d1 between two consecutive posts will be d1 = distance / ( postnumber + 1 ) The location of the first post will be xstart + d1 the location of the second post will be xstart + 2 * d1 of the third xstart + 3 * d1 etc. */ #include main() { float xstart; // x coordinate of the starting minitower float xend; // corresponding coordinate of the end minitower float distance; // the distance between start and end float d1; // the distance between two consecutive posts float location; // the location of the current post int postnumber; // the number of wooden posts to be placed at equal // intervals between the two minitowers on a straight line. int k; // a running index indicating the current post cout<<" \n Enter the coordinates xstart and xend ( in feet)."< xstart"<< endl; cin >> xstart>>xend; if( xstart > xend) cout<<" You entered the coordinates incorrectly" ; else { cout<<" enter the number of wooden posts you need ....."; cin >> postnumber; distance = xend - xstart; d1 = distance / (postnumber + 1 ); cout<<" \n The start is located at " << xstart <<" feet"<< endl; for ( k = 1 ; k <= postnumber ; k++ ) { location = xstart + (float)k * d1 ; cout<<" The post # "<< k << " is at " << location <<" feet"<< endl ; } cout<<" \n The end is located at " << xend << " feet "<< endl; } cout<<" \n\n Enter e (exit) to terminate ...."; char hold; cin>>hold; } /* THE OUTPUT: Enter the coordinates xstart and xend ( in feet). Leave a space in between and make sure xend > xstart 4.5 8.98 enter the number of wooden posts you need .....9 The start is located at 4.5 feet The post # 1 is at 4.948 feet The post # 2 is at 5.396 feet The post # 3 is at 5.844 feet The post # 4 is at 6.292 feet The post # 5 is at 6.74 feet The post # 6 is at 7.188 feet The post # 7 is at 7.636 feet The post # 8 is at 8.084 feet The post # 9 is at 8.532 feet The end is located at 8.98 feet Enter e (exit) to terminate .... */