Unit #4 Homework Problem (Solution) | ||||||||||||||
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Sol4hw1
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You are given the table:
Obtain the force at time = 2.67, .3.00, and . 3.50 At time = 2.67 sec: force = 1789 + [ (2345 - 1789) / (2.89 - 2.45)] * (2.67 - 2.45) = 2067.00 N At time = 3.00 sec force = 2345 + [ (900 - 2345) / (3.12 - 2.89)] * (3.00 - 2.89) = 1653.91 N At time = 3.50 sec force = 900 + [ (897 - 900) / (3.67 - 3.12)] * (3.50 - 3.12) = 897.93
N
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Jacob Y. Kazakia ©
2001 All rights reserved
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