Unit #4 Homework Problem (Solution)
Course Outline HW & Programming Assignments
Sol4hw1

You are given the table:

Time ( seconds) Force ( in Newtons)
2.34 1256
2.45 1789
2.89 2345
3.12 900
3.67 897
4.05 1235

Obtain the force at time = 2.67,…….3.00,……and …. 3.50


At time = 2.67 sec:

force = 1789 + [ (2345 - 1789) / (2.89 - 2.45)] * (2.67 - 2.45) = 2067.00 N

At time = 3.00 sec

force = 2345 + [ (900 - 2345) / (3.12 - 2.89)] * (3.00 - 2.89) = 1653.91 N

At time = 3.50 sec

force = 900 + [ (897 - 900) / (3.67 - 3.12)] * (3.50 - 3.12) = 897.93 N


Jacob Y. Kazakia © 2001 All rights reserved