The idea behind curve sketching is to translate the quantitative information you can determine from the formula describing a function into qualitative information, interpreting the quantitative information in terms of the dynamics of the function (expressed as the graph, or picture, of the function). Conversely, given that qualitative information, you can conclude a number of things about the function that have quantatitive meaning. The two ways of understanding a function complement each other.
Because we want to extract the qualitative understanding of the function from the graph, we draw the graph by hand, not using a computer. Of course, Maple can draw all these graphs, very well (although some skill is required to get the domain and range appropriate to see all the features of the function). Certainly, it's a good idea to use Maple to check your work.
The primary use of the first derivative in graphing is that, if f¢(x) > 0 , then the function is increasing, and if f¢(x) < 0 , the function is decreasing (as you move from left to right).
We're going to deal with a function f . A few points are of special interest, called critical points. As we mentioned earlier, a critical point of f is a value of x for which either:
From what we mentioned earlier, it follows that the maximum or minimum value of f occurs at a critical point.
We can, however, refine the idea of a critical point. If, for x < x0 , but x close to x0 , f¢(x) < 0 , and if for x > x0 , but x close to x0 , f¢(x) > 0 , and (of course) f¢(x0) = 0 , then the graph of f is dipping down to f(x0) and rising away from there, that is, f has a local minimum or relative minimum at x0 .
On the other hand, if, for x < x0 , but x close to x0 , f¢(x) > 0 , and if for x > x0 , but x close to x0 , f¢(x) < 0 , and (of course) f¢(x0) = 0 , then the graph of f is rising up to f(x0) and falling away from there, that is, f has a local maximum or relative maximum at x0 .
You should try to keep straight that when we talk about a critical point, or a relative minimum point, we refer to the x (or whatever the independent variable is called), not the value of the function. Those are either called critical values (or relative minimum values), or critical numbers (et. cetera).
We can emphasize the idea of what a local maximum or minimum looks like in the following ``test''.
Theorem 1 If, at a critical point x0 , then: If, for x < x0 , but x close to x0 , f¢(x) < 0 , and if for x > x0 , but x close to x0 , f¢(x) > 0 , f has a local minimum or at x0 . If, for x < x0 , but x close to x0 , f¢(x) > 0 , and if for x > x0 , but x close to x0 , f¢(x) < 0 , f has a local maximum at x0 .
We're going to use the information we just talked about theoretically regarding the first derivative to draw reasonable graphs of the functions. Here are the examples:
Example 1 f(x) = x2-2x+3 .
Solution
Example 2 f(x) = 2x3-3x2-12x .
Exercise 1 f(x) = 3x4-4x3 .
Intercepts
Increasing/decreasing, and critical points
Here you should describe the range where f¢ is positive, and where it is negative.
Draw the graph
Well, we can't do that over the net so easily. So, instead, pick which of the following graphs looks most like the graph of that function. Choose the closest: A B C D
The second derivative, which measures the rate of change of the slope, tells about the ``curvature'' of the curve. It curves upward (concave up) where f¢¢(x) > 0 , and curves downward (concave down) where f¢¢(x) < 0 .
Theorem 2 [The Second Derivative Test]. If f(x) has a critical point at c , then: If f¢¢(c) > 0 , then f(x) has a relative minimum at c , If f¢¢(c) < 0 , then f(x) has a relative maximum at c , and If f¢¢(c) = 0 , then you can't tell whether f(x) has a relative maximum, or minimum, or neither, at c . Proof.
Find the inflection points and concavity; then sketch the curve, showing these points as well as slope and critical points.
Example 4 f(x) = x1/3 .
Example 5 f(x) = x4+4x3+4x2-2 .
Exercise 2 f(x) = x4-2x3 .
Find all intecepts
Increasing/decreasing, critical points
Find where the curve is increasing/decreaing, and find all critical points and values.
Concavity and points of inflection
Find where the curve is concave up or concave down, and find all inflection points (sometimes, finding the values at the critical points is messy, but do what you can).
There are a number of techniques to apply to produce a reasonable qualitative picture of the graph of a function. The idea is to be able to translate analytic properties of the function to the qualitative behavior illustrated in the graph. Here are the points (pun unintended) you should make sure to include in any sketch.
Domain: Your graph should give an idea of the domain of the function. This does not mean that you have to include x 's out to +¥, but certainly if the domain is restricted, the picture needs to illustrate that.
Intercepts: Finding the y -intercept of a graph, where the function crosses the y -axis, gives you a good place to start drawing the graph. Finding the x -intercepts, where the function has value 0 , is often harder, but it is a good thing to include if you can find them.
Symmetry/Periodicity: Look for whether the function is even f(-x) = f(x) or odd f(-x) = -f(x) . Even functions are symmetric about the y -axis, so whatever the graph is for x > 0 is mirrored for x < 0 . Odd functions are upside-down symmetric about the y -axis, or are ``symmetric about the origin''. Also look for periodicity, such as with trigonometric functions, that is, for some number a , called the period of the function, for which f(x+a) = f(x) . Then, the graph is simply repeated period after period.
Asymptotes: An asymptote is a line, vertical, horizontal, or slanted, which the graph of the function approximates ``near infinity''. This was already discussed somewhat back in Chapter 1, when we were dealing with infinite limits.
More About Asymptotes
Then draw the curve, showing these points.
Example 6 f(x) = 2x+3x+1 Solution
Exercise 3 f(x) = exx . Asymptotes
Concavity, and inflection points
Exercise 4 y = xx+1 . Asymptotes
Look for a slant asymptote for this one.
Example 7 y = Öx- ___Öx-1 . Solution
Exercise 5 y = 2cosx+sin(2x). Asymptotes
Example 8 y = xe1/x. Solution
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Copyright (c) 2000 by David L. Johnson.