Problem 1
Compute
lim
x® 3
x2-9
x2-2x-3
.
The problem with this limit is that, as x approaches 3 , both the
numerator and the denominator approach 0. So, the fraction becomes
|
We want to use the rather obvious property that if two function are the same, except at 3 (say), then their limits at 3 will also be the same. In this case, that means we have to factor the numerator and the denominator, and see if that will let us make sense of the fraction for numbers near (maybe even at) x = 3 . You should be able to see why the 0/0 happens once you factor the expression.
By David L. Johnson, last modified 3/10/00.